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If the probability of a horse A winning a race is $1 / 4$ and the probability of a horse $B$ winning the same race is $1 / 5$, then the probability that either of them will win the race is
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The correct answer is:
$\frac{9}{20}$
$P(A \cup B)=P(A)+P(B)=\frac{1}{4}+\frac{1}{5}=\frac{9}{20}$
$\{$ Since events are mutually exclusive, so $P(A \cap B)=0\}$
$\{$ Since events are mutually exclusive, so $P(A \cap B)=0\}$
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