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If the slope of the line \(a x+(3-a) y+7=0\) is 7 then the value of integral part of ' \(a\) ' is
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Given line \(a x+(3-a) y+7=0\)
Given slope \(=7\)
\(\begin{aligned}
\Rightarrow \frac{-a}{3-a} & =7 \\
\frac{a}{3-a} & =7 \\
a & =7 a-21 \\
6 a & =21 \\
a & =\frac{7}{2} \\
a & =3.5 \\
a & =3+0.5 \\
{[a] } & =3
\end{aligned}\)
Hence, option (a) is correct.
Given slope \(=7\)
\(\begin{aligned}
\Rightarrow \frac{-a}{3-a} & =7 \\
\frac{a}{3-a} & =7 \\
a & =7 a-21 \\
6 a & =21 \\
a & =\frac{7}{2} \\
a & =3.5 \\
a & =3+0.5 \\
{[a] } & =3
\end{aligned}\)
Hence, option (a) is correct.
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