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If the sum of the slopes of the lines given by \(4 x^2+2 \lambda x y-7 y^2=0\) is equal to the product of the slopes, then \(\lambda\) is equal to
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Verified Answer
The correct answer is:
-2
\(\begin{aligned}
& 4 x^2+2 \lambda x y-7 y^2=0 \\
& a=4,2 h=2 \lambda, b=-7
\end{aligned}\)
Given, sum of slopers = product of slopers
\(\begin{aligned}
m_1+m_2 & =m_1 m_2 \\
\frac{-2 h}{b} & =\frac{a}{b} \\
\frac{-2 \lambda}{-7} & =\frac{4}{-7} \\
\lambda & =-2
\end{aligned}\)
Hence, option (c) is correct.
& 4 x^2+2 \lambda x y-7 y^2=0 \\
& a=4,2 h=2 \lambda, b=-7
\end{aligned}\)
Given, sum of slopers = product of slopers
\(\begin{aligned}
m_1+m_2 & =m_1 m_2 \\
\frac{-2 h}{b} & =\frac{a}{b} \\
\frac{-2 \lambda}{-7} & =\frac{4}{-7} \\
\lambda & =-2
\end{aligned}\)
Hence, option (c) is correct.
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