Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
If the sum to infinity of the series 1+4x+7x2+10x3+.. is 3516, where x<1, then x is equal to
MathematicsSequences and SeriesJEE Main
Options:
  • A 197
  • B 15
  • C 14
  • D 47
Solution:
1859 Upvotes Verified Answer
The correct answer is: 15
S=1+4x+7x2+10x3+..
xS=x+4x2+7x3+...
On subtracting, we get,
S1-x=1+3x+3x2+3x3+...
=1+3x11-x,x<1
1-xS=1-x+3x1-x=1+2x1-x
S=1+2x1-x2=3516 (given)
16+32x=35+35x2-70x
35x2-102x+19=0
5x-17x-19=0
x=15,197
But, x<1x=15

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.