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Question: Answered & Verified by Expert
If \((\vec{a} \times \vec{b})^2+(\vec{a} \cdot \vec{b})^2=676\) and \(|\vec{b}|=2\) then \(|\vec{a}|\) is equal to
MathematicsVector AlgebraJEE Main
Options:
  • A 13
  • B 26
  • C 39
  • D None of these
Solution:
2505 Upvotes Verified Answer
The correct answer is: 13
\(\begin{aligned} &(\vec{a} \times \vec{b})^2+(\vec{a} \cdot \vec{b})^2=676 \\ &(|\vec{a}| \cdot|\vec{b}| \sin \theta \hat{n})^2+(|\vec{a}| \cdot|\vec{b}| \cos \theta)^2=676 \\ & \Rightarrow a^2 b^2 \sin ^2 \theta+a^2 b^2 \cos ^2 \theta=676\left[(\hat{n})^2=1\right] \\ & a^2 b^2\left(\sin ^2 \theta+\cos ^2 \theta\right)=676 \Rightarrow a^2=\frac{676}{b^2}=\frac{676}{4} \\ &|\vec{a}|=\sqrt{\frac{676}{4}} \Rightarrow|\vec{a}|=\frac{26}{2} \Rightarrow|\vec{a}|=13\end{aligned}\)

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