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If $\frac{x^4}{(x-1)^2(x+1)}=\mathrm{A} x+\mathrm{B}+\frac{\mathrm{P}}{(x-1)}+\frac{\mathrm{Q}}{(x-1)^2}+\frac{\mathrm{R}}{x+1}$, then $2 \mathrm{AP}-\mathrm{BQ}+\mathrm{R}=$
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The correct answer is:
$\frac{13}{4}$
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