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Question: Answered & Verified by Expert
If $x_1$ be the size of the magnified image and $x_2$ the size of the diminished image in Lens Displacement Method, then the size of the object is :
PhysicsExperimental PhysicsWBJEEWBJEE 2010
Options:
  • A $\sqrt{x_1 x_2}$
  • B $x_1 x_2$
  • C $x_1^2 x_2$
  • D $x_1 x_2^2$
Solution:
1983 Upvotes Verified Answer
The correct answer is: $\sqrt{x_1 x_2}$
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