Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
If x=2+223+213, then x3-6x2+6x=
MathematicsQuadratic EquationTS EAMCETTS EAMCET 2021 (05 Aug Shift 1)
Options:
  • A 3
  • B 2
  • C 1
  • D 0
Solution:
2181 Upvotes Verified Answer
The correct answer is: 2

x=2+223+213x-2=223+213

Cubing both sides i.e. x-23=223+2133

x3-6x2+12x-8=22+21+3·223·213·223+213 (Using a-b3=a3-3a2b+3ab2-b3, a+b3=a3+b3+3aba+b, amn=amn)

x3-6x2+12x-8=6+3·2·x-2 (Using am·an=am+n)

x3-6x2+6x=2

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.