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Question: Answered & Verified by Expert
If $-\mathrm{x}^{2}+3 \mathrm{x}+4>0$, then which one of the following is correct?
MathematicsApplication of DerivativesNDANDA 2007 (Phase 1)
Options:
  • A $x \in(-1,4)$
  • B $x \in[-1,4]$
  • C $\mathrm{x} \in(\infty,-1) \cup(4, \infty)$
  • D $\mathrm{x} \in(-\infty,-1] \cup[4, \infty)$
Solution:
1774 Upvotes Verified Answer
The correct answer is: $x \in(-1,4)$
$-x^{2}+3 x+4>0$
$\Rightarrow x^{2}-3 x-4 < 0 \Rightarrow(x-4)(x+1) < 0$
Noting the sign of expression around $-1$ and 4 , we use way curve method.

$\Rightarrow \mathrm{x} \in(-1,4)$

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