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If $\mathrm{X}$ is a random variable with the following probability distribution
$\begin{array}{|l|c|c|c|}
\hline \mathrm{X}=x & -3 & 6 & 9 \\
\hline \mathrm{P}(\mathrm{X}=x) & \frac{1}{6} & \frac{1}{2} & \frac{1}{3} \\
\hline
\end{array}$
then the variance of $\mathrm{X}$ is
Options:
$\begin{array}{|l|c|c|c|}
\hline \mathrm{X}=x & -3 & 6 & 9 \\
\hline \mathrm{P}(\mathrm{X}=x) & \frac{1}{6} & \frac{1}{2} & \frac{1}{3} \\
\hline
\end{array}$
then the variance of $\mathrm{X}$ is
Solution:
2191 Upvotes
Verified Answer
The correct answer is:
$\frac{65}{4}$
No solution. Refer to answer key.
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