Search any question & find its solution
Question:
Answered & Verified by Expert
If $x=t+\frac{1}{t}$ and $y=t-\frac{1}{t}$, the $\frac{\mathrm{d} y}{\mathrm{~d} x}=$
Options:
Solution:
2622 Upvotes
Verified Answer
The correct answer is:
$\frac{t^2+1}{t^2-1}$
$\frac{\mathrm{d} y}{\mathrm{~d} x}=\frac{\frac{\mathrm{d} y}{\mathrm{~d} t}}{\frac{\mathrm{d} x}{\mathrm{~d} t}}=\frac{1+\frac{1}{t^2}}{1-\frac{1}{t^2}}=\frac{t^2+1}{t^2-1}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.