If y = f x satisfies the conditions of Rolle's theorem in 2,6 , then ∫ 2 6 f ′ x dx is equal to

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Question: Answered & Verified by Expert

If

y = f (x)

satisfies the conditions of Rolle's theorem in

[2,6],

then

\int_{2}^{6} f^{'} (x) dx

is equal to

MathematicsApplication of DerivativesJEE Main

Options:

A $2$
B $0$
C $4$
D $6$

Solution:

1409 Upvotes Verified Answer

The correct answer is:

0

Since

f (x)

satisfies the conditions of Rolle's Theorem so

f (2) = f (6)

Now, given integral

= {(f (x))}_{2}^{6} = f (6) - f (2) = 0

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