If y = ( x + 1 x 2 ) x and d x d y = y [ g ( x ) + lo g ( x + 1 x 2 ) ] , then g ( x ) =

Open MARKS Web Download App

Search any question & find its solution

Question: Answered & Verified by Expert

If $y=\left(\frac{x^{2}}{x+1}\right)^{x}$ and $\frac{d y}{d x}=y\left[g(x)+\log \left(\frac{x^{2}}{x+1}\right)\right]$, then $g(x)=$

MathematicsDifferentiationMHT CETMHT CET 2020 (13 Oct Shift 2)

Options:

A $\frac{x+2}{x+1}$
B $x \log \left(\frac{x^{2}}{x+1}\right)$
C $\frac{x^{2}}{x+1}$
D $\frac{x-1}{x+2}$

Solution:

2575 Upvotes Verified Answer

The correct answer is: $\frac{x+2}{x+1}$

No solution

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.

Use on iOS or Desktop Download from Google Play