If y = x sin x , then, y 1 d x d y = x 1 + cot x, d x d y = x 1 + cot x, y 1 d x d y = x 1 − cot x, None of these

y = x sin x ⇒ d x d y = x cos x + sin x ⇒ y 1 d x d y = cot x + x 1

If y = x sin x , then

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If $y=x \sin x$, then

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The correct answer is: $\frac{1}{y} \frac{d y}{d x}=\frac{1}{x}+\cot x$

$y=x \sin x \Rightarrow \frac{d y}{d x}=x \cos x+\sin x \Rightarrow \frac{1}{y} \frac{d y}{d x}=\cot x+\frac{1}{x}$

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