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Question: Answered & Verified by Expert
In a ABC, if b=10acos2C2+ccos2A2=15 and the area of the triangle is 153 sq. units, then cotB2=
MathematicsProperties of TrianglesTS EAMCETTS EAMCET 2020 (09 Sep Shift 1)
Options:
  • A 32
  • B 12
  • C 23
  • D 53
Solution:
2564 Upvotes Verified Answer
The correct answer is: 53

We have, acos2C2+ccos2A2=15

a1+cosC2+c1+cosA2=15

a+c+acosC+ccosA=30

a+b+c=30

a+c=20

s=15    ...1

Now =153=ss-as-bs-c

225×3=15×15-a×5×15-c

ac=84     ...2

also 153=12×84×sinB

sinB=15314

cosB=1114

Therefore, cotB2=1+cosB1-cosB

=1+11141-1114=53.

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