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Question: Answered & Verified by Expert
In a car race, sound signals emitted by the two cars are detected by a detector on the straight track at the end of the race. The frequency observed for the two cars is 330 Hz and 360 Hz respectively, while the original frequency is 300 Hz for both the cars. The race ends with a separation of 100 m between the cars. Assume both cars move with constant velocity and velocity of sound is 330 m s-1. Find the time taken by the winning car (in second).
PhysicsWaves and SoundJEE Main
Solution:
1626 Upvotes Verified Answer
The correct answer is: 4.00

330=330330v1×300  v1=30m s-1

360=330330v2×300

330v2=33012×10=275

v2=55m s-1 ; ΔV=25m s-1

100=ΔV×T    T=4s

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