In a chemical reaction, A + 2 B ⇌ K 2 C + D , the initial concentration of B was 1.5 times of the concentration of A , but the equilibrium concentrations of A and B were found to be equal. The equilibrium constant K for the chemical reaction is:

Question

In a chemical reaction, A + 2 B ⇌ K 2 C + D , the initial concentration of B was 1.5 times of the concentration of A , but the equilibrium concentrations of A and B were found to be equal. The equilibrium constant K for the chemical reaction is:, 1, 4, 1 4, 16

MARKS App · Accepted Answer

A + 2 B ⇌ 2 C + D Initial conc. of [A] = a , [B] = 1.5a , [C] = 0 and [D] = 0 At equilibrium [A] = (a - x) , [B] = 1.5(a - 2x) , [C] = 2x and [D] = x At equilibrium a - x = 1.5 a - 2 x 0.5 a = x a = 2 x k C = 2 x 2 x a - x 1.5 a - 2 x 2 = 4 x 2 . x x x 2 = 4

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