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In a face centred cubic lattice, atom A occupies the corner positions and atom B occupies the face centre positions. If one atom of $B$ is missing from one of the face centred points, the formula of the compound is
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The correct answer is:
$\mathrm{A}_2 \mathrm{~B}_5$
$\mathrm{A}_2 \mathrm{~B}_5$
Effective no.of $A$ atoms $=\frac{1}{8} \times 8=1$
Effective no.of $B$ atoms $=\frac{1}{2} \times 5$ (One is missing) $=\frac{5}{2}$
Therefore formula is $A_1 B_{\frac{5}{2}}=A_2 B_5$
Effective no.of $B$ atoms $=\frac{1}{2} \times 5$ (One is missing) $=\frac{5}{2}$
Therefore formula is $A_1 B_{\frac{5}{2}}=A_2 B_5$
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