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Question: Answered & Verified by Expert
In a plane electromagnetic wave travelling in free space, the electric field component oscillates sinusoidally at a frequency of 2.0×1010 Hz and amplitude 48 V m-1. Then the amplitude of oscillating magnetic field is: (Speed of light in free space = 3×108 m s-1)
PhysicsElectromagnetic WavesNEETNEET 2023 (All India)
Options:
  • A 1.6×10-6 T
  • B 1.6×10-9 T
  • C 1.6×10-8 T
  • D 1.6×10-7 T
Solution:
2969 Upvotes Verified Answer
The correct answer is: 1.6×10-7 T

Frequency of oscillation =2×1010 Hz
Given c=3×108 m s-1,

Electric field amplitude E0=48 V m-1

Using the formula, c=E0B0

The amplitude of the oscillating magnetic field

B0=E0c=483×108=1.6×10-7 T.

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