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Question: Answered & Verified by Expert
In a potentiometer experiment, when a cell in the secondary circuit is shunted by a resistance ' $R$ ', balancing length is ' $L_1$ '. On doubling the shunt resistance, balancing length increases to ' $L_2$ '. Internal resistance of the cell is
PhysicsCurrent ElectricityAP EAMCETAP EAMCET 2017 (24 Apr Shift 1)
Options:
  • A $\frac{2 \mathrm{R}\left(\mathrm{L}_2-\mathrm{L}_1\right)}{\mathrm{L}_1-2 \mathrm{~L}_2}$
  • B $\frac{2 \mathrm{R}\left(\mathrm{L}_2-\mathrm{L}_1\right)}{\left(2 \mathrm{~L}_1-\mathrm{L}_2\right)}$
  • C $\frac{\mathrm{R}\left(\mathrm{L}_2-\mathrm{L}_1\right)}{\mathrm{L}_1-2 \mathrm{~L}_2}$
  • D $\frac{\mathrm{R}\left(\mathrm{L}_2-\mathrm{L}_1\right)}{\left(2 \mathrm{~L}_1-\mathrm{L}_2\right)}$
Solution:
1326 Upvotes Verified Answer
The correct answer is: $\frac{2 \mathrm{R}\left(\mathrm{L}_2-\mathrm{L}_1\right)}{\left(2 \mathrm{~L}_1-\mathrm{L}_2\right)}$
No solution. Refer to answer key.

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