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In a reaction, $A+B \rightleftharpoons C+D, 40 \%$ of $B$ has reacted at equilibrium, when 1 mole of $A$ was heated with 1 mole of $B$ in a $10 \mathrm{~L}$ closed vessel. The value of $K_C$ is
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$0.44$
$\begin{aligned} & A+B \rightleftharpoons C \quad+D \\ & \text { At } t=0,1 \quad 1 \quad 0 \quad 0 \\ & \text { At equil. }(1-0.4)(1-0.4) 0.40 .4 \\ & =0.6 \quad=0.6 \\ & K_c=\frac{[C][D]}{[A][B]} \\ & =\frac{0.4 \times 0.4}{0.6 \times 0.6}=0.44 \\ & \end{aligned}$
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