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In a solution of $p H=5$, more acid is added in order to reduce the $p H=2$. The increase in hydrogen ion concentration is
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1000 times
$\left[H^{+}\right]_{\mathrm{I}}=10^{-5}\left[H^{+}\right]_{\text {II }}=10^{-2}$
Thus increase in $\left[H^{+}\right]=\frac{10^{-2}}{10^{-5}}=1000$ times
Thus increase in $\left[H^{+}\right]=\frac{10^{-2}}{10^{-5}}=1000$ times
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