In a triangle A B C , b 2 sin 2 C + c 2 sin 2 B =

Question

In a triangle A B C , b 2 sin 2 C + c 2 sin 2 B =, 0, 4 Δ, 2 Δ, Δ

MARKS App · Accepted Answer

b 2 sin 2 C + c 2 sin 2 B = 4 R 2 sin 2 B 2 sin C cos C + 4 R 2 sin 2 c 2 sin B cos B ∵ a sin A = b sin B = c sin C = 2 R = 8 R 2 sin B sin C sin B cos C + cos B sin C = 8 R 2 sin B sin C sin B + C = 8 R 2 sin B sin C sin π - A = 8 R 2 sin B sin C sin A = 2 2 R sin B 2 R sin C sin A , = 2 b c sin A {Using sine rule} = 4 1 2 b c sin A = 4 ∆

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