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In an ac circuit, $V$ and I are given by $V=100 \sin (100 t)$ volts, $I=100 \sin \left(100 t+\frac{\pi}{3}\right) \mathrm{mA}$
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$2.5 watt$
$\begin{aligned} & P=V_{r m, s .} \times i_{r m, s .} \times \cos \phi=\frac{100}{\sqrt{2}} \times \frac{100 \times 10^{-3}}{\sqrt{2}} \times \cos \frac{\pi}{3} \\ & =\frac{10^4 \times 10^{-3}}{2} \times \frac{1}{2}=\frac{10}{4}=2.5 \mathrm{watt}\end{aligned}$
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