In an adsorption experiment, a graph between log ( x / m ) versus logP was found to be linear with a slope of 45 ° . The intercept on log ( x / m ) axis was found to be 0 . 3010 . The amount of gas adsorbed per gram of charcoal under a pressure of 0 . 5 atm is

Question

In an adsorption experiment, a graph between log ( x / m ) versus logP was found to be linear with a slope of 45 ° . The intercept on log ( x / m ) axis was found to be 0 . 3010 . The amount of gas adsorbed per gram of charcoal under a pressure of 0 . 5 atm is, 0 . 5 g, 1 . 0 g, 1 . 5 g, 0 . 75 g

MARKS App · Accepted Answer

According to the Freundlich's Adsorption Isotherm, x m = k · p 1 / n By taking the log both sides, log x m = logk + 1 n logp So, slope = 1 n ⇒ tan 45 ° = 1 ( n = 1 ) logK = 0 . 3010 ⇒ k = 2 x m = 2 ( 0 . 5 ) 1 n x m = 1 Hence, the amount of gas adsorbed per gram of charcoal under a pressure of 0 . 5 atm is 1 . 0 g

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