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In an $L-C-R$ circuit inductance is changed from $L$ to $L / 2$. To keep the same resonance frequency, $C$ should be changed to
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The correct answer is:
$2 C$
$v=\frac{1}{\sqrt{L C}}$
When $L$ is changed to $L / 2, C$ must be changed to 2 C to keep $v$ same.
When $L$ is changed to $L / 2, C$ must be changed to 2 C to keep $v$ same.
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