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Question: Answered & Verified by Expert
In an LCR series circuit, an inductor 30 mH and a resistor 1 Ω are connected to an AC source of angular frequency 300 rad s-1. The value of capacitance for which the current leads the voltage by 45° is 1x×10-3 F. Then the value of x is
PhysicsAlternating CurrentJEE MainJEE Main 2021 (20 Jul Shift 1)
Solution:
1516 Upvotes Verified Answer
The correct answer is: 3
tanϕ=xC-xLR
tan45=xC-xLR
xC-xL=R
1ωC-ωL=R
1ωC-300×0.03=1
1ωC=10
C=110ω=110×300
C=13×10-3
X=3

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