To solve this question we have to use the concept that "the resultant electric field at any point inside a conducting shell due to all outside charges is zero, " and that "E at any internal point due to uniformly charged conducting spherical shell is zero."
Consider any point P inside the shell, at P the resultant electric field due to I, II and charge on outer surface of shell must be zero.


               


${\mathrm{E}}_{\mathrm{P}}={\mathrm{E}}_{\mathrm{I}}+{\mathrm{E}}_{\mathrm{II}}+{\mathrm{E}}_{\mathrm{outer} \mathrm{surface} \mathrm{charge}}=0$

But ${\text{E}}_{\text{I}}+{\text{E}}_{\text{II}}\ne 0$. So ${\text{E}}_{\text{outer surface charge}}\ne 0$ it means charge distribution is outer surface of shell is non-uniform.