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In conversion of moving coil galvanometer into an ammeter of required range, the resistance of ammeter so formed is
$[\mathrm{s}=$ shunt and $\mathrm{G}=$ resistance of galvanometer $]$
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$[\mathrm{s}=$ shunt and $\mathrm{G}=$ resistance of galvanometer $]$
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2230 Upvotes
Verified Answer
The correct answer is:
$\frac{S G}{S+G}$
(D)
$\begin{array}{l}
\frac{1}{R}=\frac{1}{G}+\frac{1}{S}=\frac{G+S}{G S} \\
\therefore R=\frac{G S}{G+S}
\end{array}$
$\begin{array}{l}
\frac{1}{R}=\frac{1}{G}+\frac{1}{S}=\frac{G+S}{G S} \\
\therefore R=\frac{G S}{G+S}
\end{array}$
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