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In following reaction
$\mathrm{yMnO}_4^{-}+x \mathrm{H}^{+}+\mathrm{C}_2 \mathrm{O}_4^{-} \rightarrow y \mathrm{Mn}^{++}+2 \mathrm{CO}_2+\frac{x}{2} \mathrm{H}_2 \mathrm{O}$ $x$ and $y$ are
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$\mathrm{yMnO}_4^{-}+x \mathrm{H}^{+}+\mathrm{C}_2 \mathrm{O}_4^{-} \rightarrow y \mathrm{Mn}^{++}+2 \mathrm{CO}_2+\frac{x}{2} \mathrm{H}_2 \mathrm{O}$ $x$ and $y$ are
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Verified Answer
The correct answer is:
16 and 2
$2 \mathrm{MnO}_4^{-}+16 \mathrm{H}^{+}+\mathrm{C}_2 \mathrm{O}_4^{--} \rightarrow 2 \mathrm{Mn}^{+2}+2 \mathrm{CO}_2+8 \mathrm{H}_2 \mathrm{O}$
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