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In Hardy-Weinberg equation, the frequency of heterozygous individual is represented by:
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The correct answer is:
2pq
Hardy-Weinberg principle says that the sum total of all the allelic frequencies of a gene is 1 and the possible frequencies of above mentioned genotypes, i.e., AA, aa and Aa are p2, q2 and 2pq, respectively. So mathematically this statement can be written as
p2 + 2pq + q2 = 1, where
= Homozygous dominant individuals
2pq = Heterozygous individuals
= Homozygous recessive individuals
p2 + 2pq + q2 = 1, where
= Homozygous dominant individuals
2pq = Heterozygous individuals
= Homozygous recessive individuals
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