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In hydrogen azide, the bond orders of bonds (I) and (II) are ______.
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The correct answer is:
I $ < 2$, II $>2$
I $ < 2$, II $>2$
As in the resonance structure of hydrogen azide, it can be seen that number of $\mathrm{N}-\mathrm{N}$ bonds is $\leq 2$
Hence for bond (I), bond order will be $ < 2$ whereas for bond (II), number of bond $\geq 2$.
Thus its bond order will be $>2$.
Hence for bond (I), bond order will be $ < 2$ whereas for bond (II), number of bond $\geq 2$.
Thus its bond order will be $>2$.
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