Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Open MARKS Web Download App
Search any question & find its solution
Question: Answered & Verified by Expert
In the experiment to determine the internal resistance of a cell (E1) using potentiometer, the resistance drawn from the resistance box is ${ }^{\prime} \mathrm{R}^{\prime}$. The potential difference across the balancing length of the wire is equal to the terminal potential difference (V) of the cell. The value of internal resistance (r) of the cell is
PhysicsCurrent ElectricityMHT CETMHT CET 2020 (13 Oct Shift 2)
Options:
  • A $\mathrm{R}\left(\frac{\mathrm{E}_{1}}{\mathrm{~V}}+1\right)$
  • B $\mathrm{R}\left(\frac{\mathrm{V}}{\mathrm{E}_{1}}-1\right)$
  • C $\mathrm{R}\left(\frac{\mathrm{V}}{\mathrm{E}_{1}}+1\right)$
  • D $\mathrm{R}\left(\frac{\mathrm{E}_{1}}{\mathrm{~V}}-1\right)$
Solution:
2525 Upvotes Verified Answer
The correct answer is: $\mathrm{R}\left(\frac{\mathrm{E}_{1}}{\mathrm{~V}}-1\right)$
Theory question

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.

Use on iOS or Desktop Download from Google Play