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In the given circuit, find the voltage drop \(V_L\) in the load resistance \(R_L\).
Solution:
2326 Upvotes
Verified Answer
The correct answer is:
\(3 \mathrm{~V}\)
Hint : 
\(\mathrm{i}=\frac{9}{300} \mathrm{~A}\)
So, \(V_a-V_a=\frac{9}{300} \times 100=3 V\)
So, diode is not activated,
So, voltage across load is \(3 \mathrm{~V}\).

\(\mathrm{i}=\frac{9}{300} \mathrm{~A}\)
So, \(V_a-V_a=\frac{9}{300} \times 100=3 V\)
So, diode is not activated,
So, voltage across load is \(3 \mathrm{~V}\).
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