Search any question & find its solution
Question:
Answered & Verified by Expert
In the reaction, $A \rightarrow$ products, If the concentration of the reactant is doubled rate of the reaction remains unchanged. The order of the reaction with respect to $\mathrm{A}$ is
Options:
Solution:
1304 Upvotes
Verified Answer
The correct answer is:
$0$
$\mathrm{r}_1=\mathrm{k}[\mathrm{A}]^{\mathrm{n}}$ and $\mathrm{r}_2=\mathrm{k}[2 \mathrm{~A}]^{\mathrm{n}}$
$\because \quad \mathrm{r}_1=\mathrm{r}_2 \quad \therefore \mathrm{k}[\mathrm{A}]^{\mathrm{n}}=\mathrm{k}(2[\mathrm{~A}])^{\mathrm{n}}$
or, $2^n=1$
or, $2^{\mathrm{n}}=2^{\circ} \Rightarrow \mathrm{n}=0$
It is a zero order reaction.
$\because \quad \mathrm{r}_1=\mathrm{r}_2 \quad \therefore \mathrm{k}[\mathrm{A}]^{\mathrm{n}}=\mathrm{k}(2[\mathrm{~A}])^{\mathrm{n}}$
or, $2^n=1$
or, $2^{\mathrm{n}}=2^{\circ} \Rightarrow \mathrm{n}=0$
It is a zero order reaction.
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.