Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
In the titration of mohr salt against $\mathrm{KMnO}_{4}$, the indicator used is
ChemistryRedox ReactionsCOMEDKCOMEDK 2019
Options:
  • A diphenyl amine
  • B $\mathrm{KMnO}_{4}$
  • C phenolphthalein
  • D methyl orange
Solution:
2983 Upvotes Verified Answer
The correct answer is: $\mathrm{KMnO}_{4}$
In the titration of Mohr's salt with $\mathrm{KMnO}_{4}$, the indicator used is $\mathrm{KMnO}_{4}$ itself. Because $\mathrm{KMnO}_{4}$ is very intense purple in colour. When, the solution changes to pink, end point is noted.
$\underset{\text { Dark purple }}{\mathrm{MnO}_{4}^{-}} \stackrel{\text { Reduction with }}{\stackrel{\text { Mohr's salt }}{\longrightarrow}} \underset{\text { Pink }}{\mathrm{Mn}^{2+}}$

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.