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Question: Answered & Verified by Expert
In Young's double slit experiment, the $10^{\text {th }}$ maximum of wavelength ' $\lambda_1$ ' is at a distance of ' $\mathrm{Y}_1$ ' from the central maximum. When the wavelength of the source is changed to ' $\lambda_2$ ', $5^{\text {th }}$ maximum is at a distance ' $Y_2$ ' from the central maximum. The ratio $\frac{\mathrm{Y}_1}{\mathrm{Y}_2}$ is
PhysicsWave OpticsMHT CETMHT CET 2021 (22 Sep Shift 1)
Options:
  • A $\frac{2 \lambda_1}{\lambda_2}$
  • B $\frac{\lambda_2}{2 \lambda_1}$
  • C $\frac{2 \lambda_2}{\lambda_1}$
  • D $\frac{\lambda_1}{2 \lambda_2}$
Solution:
2999 Upvotes Verified Answer
The correct answer is: $\frac{2 \lambda_1}{\lambda_2}$
$\begin{aligned} & Y_1=\frac{10 \lambda_1 D}{d}, Y_2=\frac{5 \lambda_2 D}{d} \\ & \therefore \frac{Y_1}{Y_2}=\frac{10 \lambda_1}{5 \lambda_2}=\frac{2 \lambda_1}{\lambda_2}\end{aligned}$

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