Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
In Young's double-slit experiment the intensity at a point where the path difference is λ 6 ( λ being the wavelength of light used) is I. If I 0 denotes the maximum intensity, I I 0 is equal to
PhysicsWave OpticsNEET
Options:
  • A 3 4
  • B 1 2
  • C 3 2
  • D 1 2
Solution:
1066 Upvotes Verified Answer
The correct answer is: 3 4
In Young's double slit experiment intensity at a point is given by

I = I 0  cos 2 ϕ 2

where ϕ = phase difference,

I 0 = maximum intensity

or      I I 0 = cos 2 ϕ 2            .......(i)

Phase difference ϕ = 2 π λ × path difference

   ϕ = 2 π λ × λ 6    or     ϕ = π 3    .......(ii)

Substitute equation (ii) in equation (i), we get

I I 0 = cos 2 π 6      or      I I 0 = 3 4 .

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.