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Integrate the function
$e^x\left(\frac{1}{x}-\frac{1}{x^2}\right)$
$e^x\left(\frac{1}{x}-\frac{1}{x^2}\right)$
Solution:
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Verified Answer
Put $\frac{e^x}{x}=t \Rightarrow e^x\left(\frac{1}{x}-\frac{1}{x^2}\right) d x=d t$
$\therefore \quad I=\int d t=t+C=\frac{e^x}{x}+\mathrm{C}$
$\therefore \quad I=\int d t=t+C=\frac{e^x}{x}+\mathrm{C}$
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