Iron exhibits BCC structure at room temperature. Above 900 ° C , it transforms to FCC structure. The ratio of the density of iron at room temperature to that at 900 ° C is (assuming molar mass and atomic radii of iron remains constant with temperature)

Question

Iron exhibits BCC structure at room temperature. Above 900 ° C , it transforms to FCC structure. The ratio of the density of iron at room temperature to that at 900 ° C is (assuming molar mass and atomic radii of iron remains constant with temperature), 3 3 4 2, 4 3 3 2, 3 2, 1 2

MARKS App · Accepted Answer

BCC = 4 r = 3 a ⇒ a = 4 r 3 FCC = 4 r = 2 a ⇒ a = 4 r 2 d BCC d FCC = Z BCC × M N A a 3 Z FCC × M N A a 3 = 2 × M N A 4 r 3 3 4 × M N A × 4 r 2 3 = 3 4 3 2 .

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