It is found that if a neutron suffers an elastic collinear collision with a deuterium at rest, the fractional loss of its energy is P d , while for its similar collision with a carbon nucleus at rest, the fractional loss of energy is P c . The values of P d and P c are respectively

Question

It is found that if a neutron suffers an elastic collinear collision with a deuterium at rest, the fractional loss of its energy is P d , while for its similar collision with a carbon nucleus at rest, the fractional loss of energy is P c . The values of P d and P c are respectively, 0 , 1, 0 . 89 , 0 . 28, 0 . 28 , 0 . 89, 0 , 0

MARKS App · Accepted Answer

Since, the linear momentum is conserved, u = V 1 + 2 V 2 . e = 1 = V 2 - V 1 u (where e ⇒ the coefficient of restitution), u = V 2 - V 1 V 2 = 2 u 3 ; V 1 = - u 3 . Initial energy, = 1 2 u 2 . Final energy, = 1 2 × 1 × u 2 9 = u 2 18 . Fractional change = u 2 2 - u 2 18 u 2 2 = 0.88 u = V 1 + 12 V 2 ⇒ 1 = V 2 - V 1 u ⇒ u = V 2 - V 1 ⇒ V 2 = 2 u 13 ⇒ V 1 = - 11 u 13 . Change in energy, = u 2 - 11 u 13 2 × 100 = 0.294

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