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Let $A B C D E F$ be a regular hexagon with the vertices $A, B, C, D, E$ and $F$ counter clockwise. Then, the vector $\mathbf{A B}+\mathbf{B C}$ is equal parallel to
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Verified Answer
The correct answer is:
$F E+E D$
$$
\begin{aligned}
\mathbf{A B}+\mathbf{B C} & =\mathbf{A C} \\
\text { and } \mathbf{F E}+\mathbf{E D} & =\mathbf{F D}
\end{aligned}
$$
Since, $A B C D E F$ is regular hexagon.
AC must be parallel to FD.
$\therefore \mathbf{A B}+\mathbf{B C}$ is parallel to $\mathbf{F E}+\mathbf{E D}$.
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