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Let $\mathrm{A}=\{(\mathrm{n}, 2 \mathrm{n}): \mathrm{n} \in \mathrm{N}\}$ and $\mathrm{B}=\{(2 \mathrm{n}, 3 \mathrm{n}): \mathrm{n} \in \mathrm{N}\} .$ What is A $\cap$ B equal to ?
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The correct answer is:
$\phi$
$\mathrm{A}=\{(\mathrm{n}, 2 \mathrm{n}): \mathrm{n} \in \mathrm{N}\}$ and $\mathrm{B}=\{(2 \mathrm{n}, 3 \mathrm{n})\}: \mathrm{n} \in \mathrm{N}$
Listing few members of each set $\mathrm{A}=\{(1,2),(2,4),(3,6), \ldots\}$
$\mathrm{B}=\{(2,3),(4,6),(6,9) \ldots \ldots\}$
There is no member common to both these sets, hence $A \cap B=\phi$
Listing few members of each set $\mathrm{A}=\{(1,2),(2,4),(3,6), \ldots\}$
$\mathrm{B}=\{(2,3),(4,6),(6,9) \ldots \ldots\}$
There is no member common to both these sets, hence $A \cap B=\phi$
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