Search any question & find its solution
Question:
Answered & Verified by Expert
Let $\omega$ be a complex cube root of unity with $\omega \neq 1$ and $P=\left[p_{i j}\right]$ be a $2 \times 2$ matrix with $p_{i j}=\omega^{i+j}$. For $P^2 \neq 0$ if $P^k=P$, then $k$ is equal to
Options:
Solution:
1490 Upvotes
Verified Answer
The correct answer is:
57
No solution. Refer to answer key.
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.