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Question: Answered & Verified by Expert
Let α,β,γ be the real roots of the equation, x3+ax2+bx+c=0, (a,b,cR and a,b0). If the system of equations (in, u,v,w) given by αu+βv+γw=0, βu+γv+αw=0, γu+αv+βw=0 has non-trivial solution, then the value of a2b is
MathematicsDeterminantsJEE MainJEE Main 2021 (18 Mar Shift 1)
Options:
  • A 5
  • B 3
  • C 1
  • D 0
Solution:
1066 Upvotes Verified Answer
The correct answer is: 3

Equation x3+ax2+bx+c=0 has roots α , β , γ. Therefore, 

α+β+γ=-a

αβ+βγ+γα=b

Since the given system of equations has non-trivial solutions,

we have 

αβγβγαγαβ=0

or α3+β3+γ3-3αβγ=0

or α+β+γ α2+β2+γ2-αβ-βγ-γα=0

or α+β+γ α+β+γ2-3αβ+βγ+γα=0

  -aa2-3b=0

or a2/b=3

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