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Question: Answered & Verified by Expert

Let σ be the uniform surface charge density of two infinite thin plane sheets shown in figure. Then the electric fields in three different region EI , EII and EIII

 

PhysicsElectrostaticsJEE MainJEE Main 2023 (01 Feb Shift 1)
Options:
  • A EI=2σ0n^,EII=0,EIII=2σ0n^
  • B EI=0,EII=σ0n^,EIII=0
  • C EI=σ20n^,EII=0,EIII=σ20n^
  • D EI=-σ0n^,EII=0,EIII=σ0n^
Solution:
2139 Upvotes Verified Answer
The correct answer is: EI=-σ0n^,EII=0,EIII=σ0n^

Electric field due to charged sheet for charge density +σ is E=+σ20 and for -σ is E=-σ20.

Assuming RHS to be n^

EI=σ20-n^+σ20-n^=-σ0n^  (leftwards)

EII=σ20-n^+σ20n^=0

EIII=σ20n^+σ20n^=σ0n^    (rightwards)

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