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Let $D$ be the domain of a twice differentiable function $f$. For all $x \in D, f^{\prime \prime}(x)+f(x)=0$ and $f(x)=\int g(x) d x+$ constant. If $h(x)=\{\mathrm{f}(x)\}^2+\{g(x)\}^2$ and $h(0)=5$, then $h(2015)-h(2014)$ is equal to
MathematicsFunctionsAP EAMCETAP EAMCET 2015
Options:
  • A $5$
  • B $3$
  • C $0$
  • D $1$
Solution:
1609 Upvotes Verified Answer
The correct answer is: $0$
No solution. Refer to answer key.

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