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Let $f: N \rightarrow Y$ be a function defined as $f(x)=4 x+3$, where $Y=\{y \in N: y=4 x+3$ for some $x \in N\}$. Show that $\mathrm{f}$ is invertible and its inverse is
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Verified Answer
The correct answer is:
$g(y)=\frac{y-3}{4}$
$g(y)=\frac{y-3}{4}$
Function is increasing
$$
x=\frac{y-3}{4}=g(y)
$$
$$
x=\frac{y-3}{4}=g(y)
$$
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