Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
Let $\mathrm{f}: \mathrm{R} \rightarrow \mathrm{R}$ be a continuous function satisfying $\mathrm{f}(\mathrm{x})=\mathrm{x}+\int_{0}^{\mathrm{x}} \mathrm{f}(\mathrm{t}) \mathrm{dt}$, for all $\mathrm{x} \in \mathrm{R}$. Then the number of elements in the set $\mathrm{S}=\{\mathrm{x} \in \mathrm{R} ; \mathrm{f}(\mathrm{x})=0\}$ is-
MathematicsContinuity and DifferentiabilityKVPYKVPY 2010 (SB/SX)
Options:
  • A 1
  • B 2
  • C 3
  • D 4
Solution:
1508 Upvotes Verified Answer
The correct answer is: 1
$\quad \mathrm{f}^{\prime}(\mathrm{x})=1+\mathrm{f}(\mathrm{x}) \Rightarrow \mathrm{f}(\mathrm{x})=\mathrm{e}^{\mathrm{x}}-1$
$\mathrm{f}(\mathrm{x})=0 \Rightarrow \mathrm{e}^{\mathrm{x}}=1 \quad \mathrm{x}=0 \quad$ One solution

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.