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Let $f: R \rightarrow R$ be defined by
$f(x)=\left\{\begin{array}{cc}x+2, & x \leq-1 \\ x^2, & -1 < x < 1 \\ 2-x, & x \geq 1\end{array}\right.$
Then the value of $f(-1.75)+f(0.5)+f(1.5)$ is
Options:
$f(x)=\left\{\begin{array}{cc}x+2, & x \leq-1 \\ x^2, & -1 < x < 1 \\ 2-x, & x \geq 1\end{array}\right.$
Then the value of $f(-1.75)+f(0.5)+f(1.5)$ is
Solution:
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Verified Answer
The correct answer is:
$1$
$\begin{aligned} & f(-1.75)+f(0.5)+f(1.5) \\ &=(-1.75+2)+(0.25)+(2-1.5) \\ &=0.25+0.25+0.5 \\ &=1\end{aligned}$
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